g. %DateAdd . g. I was given code via an SR but it doesn't work (I'm able to save the code but when I try to look at the sample data, it just says "error"). 2. Asked 9 years, 7 months ago. If date1 is earlier than date2, then the result is negative. MonthDiff = DateDiff ("m", startdate, enddate) End If. The month and the last day of the month are defined by the parameter NLS_CALENDAR. 2425. fin,NEW. this will gives you the last 3 month date (from 1st of the month) WHERE date_column >= DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ()) - 3, 0) you have 3 date. FWIW, you don't need to use floor. 1 Answer. Then it calculates the number of months that have passed until your given date (@test) by fours steps: 1. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. select datediff (q,'03-30-2005','04-01-2005') will return 1. 32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc. If date1 is later than date2, then the result is positive. #1633022. See the following conditions: If date1 is later than date2, then the result is positive. I want to convert this number to years,Months,and Days. Summary: Hi Team, I am scheduling an OTBI report. 6. If you can join an external Oracle table to an OutSystems table, that means that both tables are on the same database, so you are using Oracle for OutSystems as well. maybe something like passing an "m" as one of the parameters. date1. These are already in hour:minute:second format! with rws as ( select timestamp'2017-03-01 01:00:00' t1, timestamp'2017-03-01 02:34:56' t2 from dual ) select t2-t1 diff_interval from rws; DIFF_INTERVAL +00 01:34:56. date_to) - (DATEDIFF(WK, evnt. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. I didn’t know you answered questions including MySQL and. Columns c ) n cross join (select cast ('2001-01-01' as date) firstdate) const. 1. Showing data 6 months greater than date parameter?? 607634 Mar 24 2010 — edited Mar 24 2010. DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date. SQL Server ignores that this is just one day. Syntax. The Overflow Blog An intuitive introduction to text embeddings. Follow. SQL Server ignores that this is just one day. Solution. I need the Oracle equivalent to the SQL Server DATEDIFF function to compute the difference between two dates. To answer your question to find all records that occurred last month. i. 1. The following example returns 2 for the months between the two dates:. Exhibit A: John Doe has served since Feb 10, 2016. This question was incorrectly asked. Calculate the difference between two dates. And you can use intervals, but using month intervals for. この番号を取得するには、次のいずれかの関数を使用: Today ()、TodateEx ()、GetFirstDate ()、GetLastDate ()、DateRoll ()。. The former produces a number representing the count of days between the two dates, while the latter produces an interval representation of the. by the way, Just new in DBeaver. Assuming that a. I believe you want: Select id, datediff (day, min (hire) max (hire)) as Difference From Employees group by id having count (terminated) < count (*) -- at least one NULL value. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. current_timestamp() returns the timestamp on the database client side. Asked 10 years, 2 months ago. 000 READDATE < DATEADD(month, DATEDIFF(month, 0, GETDATE()) - 10, 0). id = al. If IsDate (startdate) and IsDate (enddate) Then. I can get these two dates from the database in 07-JUN-12 04. For formatting functions, refer to Section 9. create or replace function FUN_DATEDIFF ( dateFrom in date, dateTo in date, interval in char return number AS result number; beginThe default is zero (0). In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. 14977 Days 7 Hours 36 Minutes 56 Seconds. mm') 16. ). In short. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). Extract a value of a date time field e. If you only need an approximation then you could just calculate the number of days difference and divide by 30. メンバーの日. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011 You get the difference in days. When a user enters JAN 2009 - I want the worksheet to show data from Jan, Feb, Mar, Apr, May and June (2009). Use DATEADD and DATEDIFF() function together in SQL query. I have a table where PurchasedDate is maintained. 2258064516 DATE_DIFF = 1. 365 days elapse between the two dates. I am looking for a way to implement the SQLServer-function datediff in PostgreSQL. Asked 2 years, 9 months ago. SQL was invented in the 1970s by IBM Computer Scientists. I want something like this. 2903225806 DATE_DIFF =. How to generate days, weeks, or months between two dates in Oracle Database June 1, 2021 | 25 minute read Chris Saxon Developer Advocate There are. The dates do not have to be in the same format in the extract file, but the format of each must be supported. SELECT DATEADD ( quarter, DATEDIFF. 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. Currently, my code just returns zero on the right side of the decimal place. Enter a date format string that describes the Date2 parameter. Should I change (edit) the title or delete and re-post the question properly? This is what I'm addressing. For example, you can use this function to find the date that is 7000 minutes from today: number = 7000, datepart = minute, date = today. T was trying do calculate age as on todays date in ORACLE but after a lot of brain storming i didn't get it. 2. date]-90) - my comparison subtracts 90 days from the max date Yes, I know,. You will see column tools as one of the tabs. 32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc. 2903225806. Goal. 18. February 28 and March 31), the fractional portion is zero, even if the days of the month are not the same. MySQL DATEDIFF: Calculating weeks, months, or years between two dates. startdate, SYSDATE) Keep in mind that MONTHS_BETWEEN() will return fractions of months, so use TRUNC() or ROUND() if you need an integer number. . I tried this selectExample: Oracle MONTHS_BETWEEN() Function - w3resourceHow to calculate age in T-SQL with years, months, and days. 2903225806. date_open END. StartDate, SYSDATE) you would use: MONTHS_BETWEEN (pr. ) Solution 1: You can use this provided your date is in the DB datetime format Solution 2: Or Solution: You do not need to use a row generator to enumerate every day to get the number of week days - it can be done using a simple calculation: From my answer here: Difference of two DATE datatype values in Oracle represents number of days between them so. Justin, the example which you gave, if that is the scenario I want the output as 1. . ) The dates and their formats are separated by a comma (,) and are defined in the Data field of the. The table contains the data about each staff member’s employment date. DateDiff compares the values of the column you specify to work out the difference, it doesn't compare both dates and give you an exact difference. g. Viewed 20k times. This is going to be short:. And determining if the date falls on a holiday (by querying against your holiday table) should be trivial. floor(months_between(sysdate, dateofbirth)/12) But, months_between function treats end of month day specially. current_time() returns the date and time on the database client side. date_from) = 1. Then you use the TO_DATE () function to. ExampleHere I need to calculate the difference of the two dates in the PostgreSQL. The difference between 1st March 2011 and 29th February 2012 is 0. January=1, February=2, etc. Parameter Description; date1, date2: Required. In Oracle SQL, I want to display the difference between two dates in the format 'x years y months z days'. i need to find the difference of two dates as the number of months: find the last day of the month of both the dates. trunc ( months_between ( end_date, start_date ) /12 ) Years, mod ( trunc ( months_between ( end_date, start_date ) ), 12 ) months, end_date - add_months (start_date,trunc ( months_between (end_date,start_date) )) days. January 30, 2004 - 7:26 pm UTC. Oracle offers its own solution, although does not have the DATEDIFF function. expression1: This is a datetime expression you’ll substract expression2 from. 2258064516. This function adds a number (a signed integer) to a datepart of an input date, and returns a modified date/time value. 208333, so the value is correct! So now that we know how subtracting dates. 242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures. Functions. The MONTHS_BETWEEN () function is used to get the number of months between dates (date1, date2). SELECT DATEADD ( year, DATEDIFF ( year, 0, GETDATE ()), 0 ) 這個 SQL 的技巧是先取得和 1900-01-01 - 也就是上面的 0 的意思，SQL Server 中的第零天 - 差幾年 (從 DATEDIFF 得到一個整數)，再用 DATEADD 加 0 來將整數再轉成日期的型態。. sql. 15 between 2 values that are 1 year, 1 month and 15 days apart. EMP table and assuming every month has 30 days: SQL> SELECT SYSDATE, 2 hiredate, 3 TRUNC (months_between. In this Document. 2) format. Asked 5 years, 9 months ago. mm') month, 13 count(*) days 14 From calendar 15 group by to_char(datum, 'yyyy. Conversion among time units is also allowed; you can add, subtract, or compare dates by using days and state. datediff (year, [bd], getdate ()) Then you need to check if the person already had this year's birthday, and if not, you need to subtract 1 from the total. Calculate the last date of the month is quite simple calculation -. The Oracle/PLSQL MONTHS_BETWEEN function returns the number of months between date1 and date2. 3 Answers. Viewed 2k times 1 I need to calculate the number of days between two dates as decimal, excluding the weekends and holidays by using a custom function in Oracle SQL. 1. SQL Database Dates is a MUST for. Converting Valid Character Strings to Dates, Times, or Timestamps. 264k 58 58 gold badges 366 366 silver badges 409 409 bronze badges. Oracle equivalent to SQL Server/Sybase. datediff ('MONTH', pr. 1. You also wouldn't prefix a function name with the @ sign. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. Viewed 4k times 1 I have a table with below structure. Share. 2 -Increment by 1 into total months count -. It works if my beginning date is the first of january and the end date the 31st of December, but does not if it stars somewhere else during the year. Multiply by 24 -- hours, multiply by 60 minutes, multiply by 60 -- seconds. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the. Each day is 1 integer. For example: print &order_date () edit 'Month dd, YYYY'. Note, that since DATEDIFF returns an integer value, the result also will be an integer. idUsage Notes¶. So, it starts with RIGHT(“00”. UPDATE Yes, he will get a 1 month difference even if it is only 1 day difference, but OP. DateAdd. SS: 差異を秒数で計算します。. Viewed 14k times 2 I'm looking to get total number of days including the Start Date and End Date, some examples below:. SELECT select AVG (months_between (SYSDATE,DOB)) AS AVERAGE_AGE_IN_MONTHS. There are many tricks to generate rows in Oracle Database. Add a number of months (n) to a date and return the same day which is n of months away. date_open are both of type date, you can simply subtract them to get a difference in days. eps Purpose MONTHS_BETWEEN returns number of months between dates date1 and date2. Click on the function name to jump to a discussion of that function. FLOOR (DATEDIFF (DAY, date_of_birth, reference_date) / 365. Answer: Oracle supports date arithmetic and you can make expressions like "date1 - date2" using date subtraction to get the difference between the two dates. 3 Answers. Examples of Results in Months. The value returned is always of data type DATE, even if you specify a different datetime data type for date. Then type a formula like one of the following. Add a number of months (n) to a date and return the same day which is n of months away. SQL> ed Wrote file afiedt. HEH! One big difference you’ll find is that adding or subtracting two date values in Oracle leaves you with a number, not a date. *You may also use the DATEDIFF function. EMPLOYEES; This is some old sample. 2425. Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46. For example, using the standard SCOTT. SQL Server DATEDIFF ( DATEPART , STARTDATE , ENDDATE ) Example: Select Datediff(mm,column1,column2) Above script will output difference in months, so based. 8. Oracle has a months_between function: AND MONTHS_BETWEEN (sysdate, s. ReturnDate)) + ' days') ELSE CAST(DATEDIFF(day, Trips. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. ArrivalDate, Trips. Function. Modified 8 years, 2 months ago. Viewed 3k times 0 I have table called C_Order. Sorted by: 3. If they are identical down to the second then, presumably, returning 0 is the right answer. There are two methods to achieve this. As with day to second intervals, the format for this is fixed. When the reporting date month is the same as the target month you can get a round up Here is a PostgreSQL function with the exact same behavior as the Oracle MONTHS_BETWEEN function. This field level rule lets you display the difference between two dates. A numeric value is returned. Note that it is subtracting the second from the first, so you must have them in this order. Improve this question. For example, adding three months or 12 days to a starting date. QUARTER: returns the quarter of the date. ) The dates and their formats are separated by a comma (,) and are defined in the Data field of the. (The valid formats 1,7,10,11 will be described later. Here’s the step by step: Use the AGE function to calculate the difference between the end date and start date. Join our newsletter and get access to exclusive content every month. If month is the same in both dates: results for month is negative. DateGroup. DateDiff. › Oracle Analytics Cloud and Server. Syntax DATEDIFF (datepart ,startdate ,enddate) datepart Abbreviations year. What's the function in Oracle that would be the equivalent to DATEDIFF in the SQL Server? On Oracle, it is an arithmetic issue: Select DATE1. User-1629274867 posted Hi, I have replaced MS Oracle Client with OPD. A) Get the difference in months of dates on the same day The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN ( DATE '2017-07-01', DATE '2017-01-01' ) MONTH_DIFF FROM. Instead, you can use simple arithmetic with Oracle dates, where subtracting one date from another gives the number of days, and where you can add an subtract days from a given date. DateDiffDay (r. Functions, you can call DateDiffDay: var ans = from t in Table1 group t by 1 into tg select tg. If you subtract from one date other you will get a count of days between this two dates. lastModified - w. Stack Overflow. In MS SQL Server, the DATEDIFF function is used to get the difference between two dates in terms of years, months, days, hours, minutes etc. This post has been answered by 630199 on Jun 1 2009. If you like this article or if you have some. montant / (datediff (NEW. You also wouldn't prefix a function name with the @ sign. In addition, with DATEDIFF () the column is an argument to the function. The next example will show the differences between two dates for each specific datapart and abbreviation. Currently I am only returning 1. 9. Returns the <date> with the specified number <interval> added to the specified <date_part> of that date. 25) This seems to be another common approach - and was also given in a comment on my question. g. If this query is executed between December 26 and December 31, you'll still. Months "m" Quarters "q" Years "y" firstWeekDay (default value is 1) is a parameter that can be used if you are returning the length of time in weeks. The SQL DATEDIFF() function is an in-built function in SQL that is used to return the difference (as a signed integer value) between two dates or times. SELECT AVG (CAST (DATEDIFF (d, DateUsed, DateExpires) AS FLOAT)) FORM tbl. (Quarter 4, 2006 - Quarter 2, 2005 = 6) DP_MONTH returns the distance between the months capturing the input dates. 0. Parameter Description; interval: Required. MONTHS_BETWEEN = 1. DATEDIFF. should work fine. Again, the expected results would be a value of 1. July 16, 2013 at 3:32 pm. Syntax. It operates according to the rules of the Gregorian calendar. Share. In Calculating Work Days you can find a good article about this subject, but as you can see it is not that advanced. DateDiff is not a function that exists in Oracle. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. FromDate, r. Do this even for a single day—e. e. Adds days, months, and years to the date and returns the result. DATEDIFF() Returns the difference between the two dates. Getting the months and years between two dates using Datediff There is a round up issue with the Datediff function. The system calculates the number of complete months between given dates. The first one involves getting the difference in days and then converting it to 'x year y month z days'. You can simply subtract two dates. Modified 7 years, 2 months ago. WHen I do. The second method uses an extract function to obtain the years, months, and days separately. Using DbFunctions, accessed via EF. (year/month/date from date) //oracle function for extracting values from date. DateDiff. SELECT --Start with total number of days including weekends (DATEDIFF (dd,@StartDate,@EndDate)+1) --Subtact 2 days for each full weekend (DATEDIFF (wk,@StartDate,@EndDate)*2) --If StartDate is a Sunday, Subtract 1 ELSE 0 END) --If EndDate is a Saturday, Subtract 1 FROM dual. Here is example with 23 hours difference: select CONVERT (VARCHAR, DATEDIFF (dd, '2018-04-12 15:54:32', '2018-04-13 14:54:32')) + ' Days ' + CONVERT (VARCHAR, DATEDIFF (hh, '2018-04-12 15:54:32', '2018-04-13 14:54:32') % 24) + ' Hours ' But the. References: ( found on on 05/15/2015 ) 1. buf 1 declare 2 total_days integer; 3 total_weeks integer; 4 remaining_days integer; 5 begin 6 total_days := date '2014-12-16' - date '2014-12-01'; 7. For example. 25) This seems to be another common approach - and was also given in a comment on my question. DATE is the main – or rather, original – datatype used in Oracle for holding dates. This can have results that you are not expecting. TASKID, PROJECT. The result is formatted according to the Format parameter. The number you’re left with is the number of days between the two days. This function is used to find the difference between two specified values of date. NEXT_MONTH: Returns the first day of the next month after the specified date. Viewed 32k times. You can't use aliases you created in the SELECT clause elsewhere in the same SELECT clause, so you need to place your FIRST_VALUE() and LAST_VALUE() functions within the DATEDIFF() function:. Take these examples: Example 1 Date 1: 10th March 2011 Date 2: 3rd Feb 2011 MONTHS_BETWEEN = 1. 1. I say ALL months as months can have 28 days (29 in a leap year), 30 days and 31 days which is why I wouldn't simply calculate the days between two dates. 0. 2 Answers Sorted by: 7 Why do you believe that it is not a good idea to subtract two dates to get the number of days between them? That's certainly the. Modified 1 year, 3 months ago. cust_field_nm eq "x_case_dte_dd" and datepart. DaysInMonth Returns the number of days in the specified month and year. DECLARE @ADate DATETIME SET @ADate = GETDATE () SELECT DAY (EOMONTH (@ADate)) AS DaysInMonth. This previous question indicates that there is a date format in Oracle that would make your year 92 into 2092 (i. Sep 16, 2015 at 5:55. For the last row return the calculated date. create table test_table ( customer_num NUMBER, card_number char(2), card_issue_date DATE, card_expire_date DATE ). Sorted by: 10. g. ops$tkyte@8i> select months_between ( end_date, start_date ), 2 trunc ( months_between ( end_date, start_date ) /12 ) Years, 3 mod (. The @DATEDIFF calculation function for Essbase returns the difference between two input dates. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. Hi team i need to get the exact month differences between two dates i am using oracle sql for my project . Connect and share knowledge within a single location that is structured and easy to search. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. SELECT PROJ_TASK. This can have results that you are not expecting. 0 months apart:Asked 3 years, 4 months ago. 1. We would like to show you a description here but the site won’t allow us. If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. sql. Q&A for work. début)/365) Here is my table and the result in the 'montant_annuel' column:The datediff function make my query run very slow (16s for 11 records), and cost also very high (~43k). You could also use the add_months function: AND s. DaysInYear Returns the number of days in the specified year. See Date and Time Data Types and Functions (Transact-SQL) for an overview of all Transact. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. You can use this methodology to determine the first day of 3 months ago, and the last day of the previous month: select DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ())-3, 0) --First day of 3 months ago select DATEADD (MONTH, DATEDIFF (MONTH, -1, GETDATE ())-1, -1) --Last Day of previous month. 10 months ago by below86. From the Oracle documentation: MONTHS_BETWEEN returns number of months between dates date1 and date2. TIMESTAMP Functions. Then it would also be helpful to be able to. That link is not for the Oracle database, it's for JavaDB (Derby). See the following conditions: If date1 is later than date2,. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. WEEK: returns the week number in the year. Add a. Can Any one help me please. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. The easiest is the connect by level method: Copy code snippet. month ( [bd]) > month (getdate ())Oracle is an object-relational database management system. PROJECTED_COMPLETION,. sql. I have a data field in my table that i would to use within my WHERE clause, to get the last 12 months dataset so for example, WHERE date between '20110323' and '20100323' Is this possible? I know I have to use something like GETDATE() or something but not quite sure how to incorporate this. show moreHere is an example that uses date functions. DATEDIFF(Day, MIN(joindate), MAX(joindate)) AS DateDifferen. Dates are always a joy to work with in any programming language, SQL not excluded. · User1416329745 posted ANSI SQL 1992. In MySql the syntax of DATEDIFF is different: DATEDIFF (date1, date2) and returns the difference date1 - date2 in days. Calculate how many years have passed: given year - 1900 2. . Access Function: DateDiff ("m",PAID_DATE,STATIC_DATE) AS Months_Between. I want to calculate the difference between two dates in OBIEE10g in Year/Months/Days format similar to the output of below SQL. So I'm guessing it is an available function for mysql, but not for oracle databases. This field level rule lets you display the difference between two dates. The syntax for the DATEDIFF function is as follows:. B. 00. To get the months or years separately, use extract. If either expression is a character or graphic string, it must not be a CLOB. MANAGER_ID, PROJECTED_DATE. If you omit fmt, then date is rounded to the. --Changing current database to the Master database allows function to be shared by everyone. This is my code. The default is date format 1. Function to count workdays. To retrieve this number, use any of the following functions: Today (), TodateEx (), GetFirstDate (), GetLastDate (), DateRoll (). Viewed 516 times 0 Everyone, the table relationship diagram for the database is the below one. 6. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). Kindly help on this. here i am trying get the month differences between two. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. PROJECT_TYPE, PROJECT. It should have been DATEDIFF NOT DATEADD with respect to the WEEK parameter. If you enter a negative parameter, the system subtracts the specified days, months, or years. If day number from start date is higher than day number from current date: days are negative. 1. It counts the number of year boundaries between two dates. Oracle Essbase計算および問合せリファレンス. SYSDATE) and subtracting a date from a timestamp (e. CREATE OR REPLACE FUNCTION dateDiff ( p_dt1 IN DATE, p_dt2 IN DATE ) RETURN NUMBER IS BEGIN RETURN p_dt1 - p_dt2; END; datediff('MONTH', pr. hourBegin, a. last_day (feb) to last_day (mar) is also commonly accepted as a "month". 000 READDATE >= DATEADD(month, DATEDIFF(month, 0, GETDATE()) - 12, 0) -- < 2016-04-01 00:00:00. SQL> ed Wrote file afiedt. A) Get the difference in months of dates on the same day The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN ( DATE '2017-07-01', DATE '2017-01-01' ) MONTH_DIFF FROM DUAL; Code language: SQL (Structured Query Language) (sql) The result is 6 months as shown below: SQL> with 2 test (start_date, end_date) as 3 (select date '2020-10-01', 4 date '2020-11-02' 5 from dual 6 ), 7 calendar as 8 (select start_date + level - 1 datum 9 from test 10 connect by level <= end_date - start_date + 1 11 ) 12 select to_char(datum, 'yyyy. Syntax:This expression: to_date(SYSDATE, 'yyyy-MM-dd') doesn't make sense. The DATEDIFF() function returns the difference between two dates. February 28 and March 28) and when the days of the month are the last day of the month (e. id = tp. For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also considered one month.